What is the tangent of 6cos(x) ?

The tangent of 6cos(x) is y=-6sin(a_{0})x+6cos(a_{0})+6a_{0}sin(a_{0})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of 6cos(x)

tangent of

6 cos (x)

y = - 6 sin (a_{0}) x + 6 cos (a_{0}) + 6 a_{0} sin (a_{0})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 cos (a_{0}))

Find the slope of

y = 6 cos (x) : \frac{d y}{d x} = - 6 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6 sin (a_{0})

Find the line with slope m=

- 6 sin (a_{0})

and passing through

(a_{0}, 6 cos (a_{0})) : y = - 6 sin (a_{0}) x + 6 cos (a_{0}) + 6 a_{0} sin (a_{0})

y = - 6 sin (a_{0}) x + 6 cos (a_{0}) + 6 a_{0} sin (a_{0})

What is the tangent of 6cos(x) ?
The tangent of 6cos(x) is y=-6sin(a_{0})x+6cos(a_{0})+6a_{0}sin(a_{0})