What is the tangent of y=(x^2)/(x+2),(2,1) ?

The tangent of y=(x^2)/(x+2),(2,1) is y= 3/4 x-1/2

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tangent of y=(x^2)/(x+2),(2,1)

tangent of

y = \frac{x ^{2}}{x + 2}, (2, 1)

y = \frac{3}{4} x - \frac{1}{2}

Solution steps

Find the slope of

y = \frac{x ^{2}}{x + 2} : \frac{d y}{d x} = \frac{x ^{2} + 4 x}{( x + 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(2, 1) : y = \frac{3}{4} x - \frac{1}{2}

y = \frac{3}{4} x - \frac{1}{2}

What is the tangent of y=(x^2)/(x+2),(2,1) ?
The tangent of y=(x^2)/(x+2),(2,1) is y= 3/4 x-1/2