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tangent 7+2e^x-4x^4x-y=9

解答

切线

7 + 2 e^{x} - 4 x^{4} x - y = 9

解答

y = (- 20 a_{0}^{4} + 2 e^{a_{0}}) x + 16 a_{0}^{5} - 2 a_{0} e^{a_{0}} + 2 e^{a_{0}} - 2

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, - 4 a_{0}^{5} - 2 + 2 e^{a_{0}})

计算

7 + 2 e^{x} - 4 x^{4} x - y = 9

的斜率:

\frac{d y}{d x} = - 20 x^{4} + 2 e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 20 a_{0}^{4} + 2 e^{a_{0}}

找到斜率 m=

- 20 a_{0}^{4} + 2 e^{a_{0}}

且穿过

(a_{0}, - 4 a_{0}^{5} - 2 + 2 e^{a_{0}})

的直线:

y = (- 20 a_{0}^{4} + 2 e^{a_{0}}) x + 16 a_{0}^{5} - 2 a_{0} e^{a_{0}} + 2 e^{a_{0}} - 2

y = (- 20 a_{0}^{4} + 2 e^{a_{0}}) x + 16 a_{0}^{5} - 2 a_{0} e^{a_{0}} + 2 e^{a_{0}} - 2

作图

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