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Popular Calculus >

y^'=cos(2x)

Solution

y^{^{'}} = cos (2 x)

Solution

y = \frac{1}{2} sin (2 x) + c_{1}

Solution steps

y^{'} (x) = cos (2 x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int cos (2 x) d x

\int cos (2 x) d x = \frac{1}{2} sin (2 x) + c_{1}

y = \frac{1}{2} sin (2 x) + c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=cos(2x) ?
The solution for y^'=cos(2x) is y= 1/2 sin(2x)+c_{1}