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Popular Calculus >

area x^2+y+4=0,y=-8

Solution

area

x^{2} + y + 4 = 0, y = - 8

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

Isolate

y

for

x^{2} + y + 4 = 0 : y = - x^{2} - 4

Apply the area formula:

\int_{- 2}^{2} - x^{2} + 4 d x

Solve

\int_{- 2}^{2} - x^{2} + 4 d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Graph

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Frequently Asked Questions (FAQ)

What is area x^2+y+4=0,y=-8 ?
The answer to area x^2+y+4=0,y=-8 is 32/3