What is the derivative of-x+8/x+1 ?

The derivative of-x+8/x+1 is -8/(x^2)-1

What is the first derivative of-x+8/x+1 ?

The first derivative of-x+8/x+1 is -8/(x^2)-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (- x + \frac{8}{x} + 1)

- \frac{8}{x ^{2}} - 1

Solution steps

\frac{d}{d x} (- x + \frac{8}{x} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} + \frac{d}{d x} (\frac{8}{x}) + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

\frac{d}{d x} (1) = 0

= - 1 - \frac{8}{x ^{2}} + 0

Simplify

= - \frac{8}{x ^{2}} - 1

What is the derivative of-x+8/x+1 ?
The derivative of-x+8/x+1 is -8/(x^2)-1
What is the first derivative of-x+8/x+1 ?
The first derivative of-x+8/x+1 is -8/(x^2)-1