What is the derivative of 4x^5-3x^4+2x^3-x+100 ?

The derivative of 4x^5-3x^4+2x^3-x+100 is 20x^4-12x^3+6x^2-1

What is the first derivative of 4x^5-3x^4+2x^3-x+100 ?

The first derivative of 4x^5-3x^4+2x^3-x+100 is 20x^4-12x^3+6x^2-1

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\frac{d}{d x} (4 x^{5} - 3 x^{4} + 2 x^{3} - x + 100)

20 x^{4} - 12 x^{3} + 6 x^{2} - 1

Solution steps

\frac{d}{d x} (4 x^{5} - 3 x^{4} + 2 x^{3} - x + 100)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{5}) - \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (2 x^{3}) - \frac{d x}{d x} + \frac{d}{d x} (100)

\frac{d}{d x} (4 x^{5}) = 20 x^{4}

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d x}{d x} = 1

\frac{d}{d x} (100) = 0

= 20 x^{4} - 12 x^{3} + 6 x^{2} - 1 + 0

Simplify

= 20 x^{4} - 12 x^{3} + 6 x^{2} - 1

(1 - x) d y - y^{2} d x = 0

\int \frac{32 x ^{2}}{( x - 24 ) ( x + 8 ) ^{2}} d x

\frac{d x}{d t} = \frac{1}{x e ^{t + 5 x}}

\int \frac{x ^{2}}{x ^{3} - 1} d x

\frac{\partial}{\partial x} (e^{- (x^{2} + x y + y^{2})})

What is the derivative of 4x^5-3x^4+2x^3-x+100 ?
The derivative of 4x^5-3x^4+2x^3-x+100 is 20x^4-12x^3+6x^2-1
What is the first derivative of 4x^5-3x^4+2x^3-x+100 ?
The first derivative of 4x^5-3x^4+2x^3-x+100 is 20x^4-12x^3+6x^2-1