What is the integral from-1 to 2 of (x^2-4x+3) ?

The integral from-1 to 2 of (x^2-4x+3) is 6

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integral from-1 to 2 of (x^2-4x+3)

\int_{- 1}^{2} (x^{2} - 4 x + 3) d x

6

Solution steps

\int_{- 1}^{2} x^{2} - 4 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{2} d x - \int_{- 1}^{2} 4 x d x + \int_{- 1}^{2} 3 d x

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} 4 x d x = 6

\int_{- 1}^{2} 3 d x = 9

= 3 - 6 + 9

Simplify

= 6

\frac{d}{d x} (\frac{1}{2} x + 3)

\int e^{2 x} - \frac{1}{2} e^{\frac{x}{2}} d x

\frac{d}{d x} (e^{- x} + \frac{x}{3})

x \to \infty lim (∣ x ∣)

\int \frac{1}{( 3 x + 4 ) ( 4 x - 1 )} d x

What is the integral from-1 to 2 of (x^2-4x+3) ?
The integral from-1 to 2 of (x^2-4x+3) is 6