What is (\partial)/(\partial y)(2ycos(x)) ?

The answer to (\partial)/(\partial y)(2ycos(x)) is 2cos(x)

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(\partial)/(\partial y)(2ycos(x))

\frac{\partial}{\partial y} (2 y cos (x))

2 cos (x)

Solution steps

\frac{\partial}{\partial y} (2 y cos (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 cos (x) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= 2 cos (x) \cdot 1

Simplify

= 2 cos (x)

y^{^{''}} + 2 y^{^{'}} + 2 y = sin (2 x)

x \to 0 + lim (e^{- \frac{5}{x}})

\int \frac{1}{- x ^{2} + 14 x + 50} d x

1 + sin^{2} (e^{5 x})

\frac{d}{d x} (ln (x + x^{2} + 3))

What is (\partial)/(\partial y)(2ycos(x)) ?
The answer to (\partial)/(\partial y)(2ycos(x)) is 2cos(x)