xyy^'=2y^2+4x^2

Lösung

x y y^{^{'}} = 2 y^{2} + 4 x^{2}

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

Schritte zur Lösung

x y y^{'} (x) = 2 y^{2} + 4 x^{2}

Solve Bernoulli ODE:

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

y = x - 4 + c_{1} x^{2}, y = - x - 4 + c_{1} x^{2}

x \to x lim (tan (x))

in v erse l a pl a ce \frac{4}{( s - 4 ) ^{3}}

\frac{\partial}{\partial x} (3 cos (2 x))

d er i v a t i v e h (x) = \frac{1}{x ^{2}} + \frac{1}{x} + x

\int \frac{cos ( a x )}{b - a sin ( a x )} d x