derivative of x^2a+a^2b+b^2x

Lösung

\frac{d}{d x} (x^{2} a + a^{2} b + b^{2} x)

2 a x + b^{2}

Schritte zur Lösung

\frac{d}{d x} (x^{2} a + a^{2} b + b^{2} x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} a) + \frac{d}{d x} (a^{2} b) + \frac{d}{d x} (b^{2} x)

\frac{d}{d x} (x^{2} a) = 2 a x

\frac{d}{d x} (a^{2} b) = 0

\frac{d}{d x} (b^{2} x) = b^{2}

= 2 a x + 0 + b^{2}

Vereinfache

= 2 a x + b^{2}

\int_{0}^{e} 4 e^{2 x} d x

\int - 2 x + 15 x^{2} - 4 x^{3} + C d x

y^{^{'}} + (\frac{7 x}{x ^{2} + 1}) y = \frac{7 x}{x ^{2} + 1}

d er i v a t i v e \frac{( ( \frac{4}{x} ) ^{2} )}{1 - \frac{4}{x}}

\frac{d}{d x} (4 + 7 x)