What is the integral of (pix^4)/(16) ?

The integral of (pix^4)/(16) is (pix^5)/(80)+C

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integral of (pix^4)/(16)

\int \frac{π x ^{4}}{16} d x

\frac{π x ^{5}}{80} + C

Solution steps

\int \frac{π x ^{4}}{16} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{π}{16} \cdot \int x^{4} d x

Apply the Power Rule

: \frac{x ^{5}}{5}

= \frac{π}{16} \cdot \frac{x ^{5}}{5}

Simplify

\frac{π}{16} \cdot \frac{x ^{5}}{5} : \frac{π x ^{5}}{80}

= \frac{π x ^{5}}{80}

Add a constant to the solution

= \frac{π x ^{5}}{80} + C

y^{^{'}} + \frac{1}{x} y = - \frac{1}{x} y^{2}, y (1) = 2

\frac{d}{d x} (lo g_{5} (\frac{4}{x ^{2} 1 - x}))

\int - 4 x^{2} e^{- 3 x} d x

x \to 1 lim ((f (x)) x^{2} - 2 x)

h \to 0 lim (h^{2} + 5^{h})

What is the integral of (pix^4)/(16) ?
The integral of (pix^4)/(16) is (pix^5)/(80)+C