What is the derivative of y=x^{2cos(x)} ?

The derivative of y=x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)

What is the first derivative of y=x^{2cos(x)} ?

The first derivative of y=x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)

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derivative of

y = x^{2 c o s (x)}

2 x^{2 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

Solution steps

\frac{d}{d x} (x^{2 c o s (x)})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{2 c o s (x)} = e^{2 c o s (x) l n (x)}

= \frac{d}{d x} (e^{2 c o s (x) l n (x)})

Apply the chain rule:

e^{2 c o s (x) l n (x)} \frac{d}{d x} (2 cos (x) ln (x))

= e^{2 c o s (x) l n (x)} \frac{d}{d x} (2 cos (x) ln (x))

\frac{d}{d x} (2 cos (x) ln (x)) = 2 (- sin (x) ln (x) + \frac{cos ( x )}{x})

= e^{2 c o s (x) l n (x)} \cdot 2 (- sin (x) ln (x) + \frac{cos ( x )}{x})

e^{2 c o s (x) l n (x)} = x^{2 c o s (x)}

= 2 x^{2 c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x})

n = 0 \sum \infty 7 (- \frac{1}{8})^{n}

x y^{^{'}} + 4 y = 2 x^{3}

t an g e n t y = 7 x + 2, (2, 4)

\int e^{- 16 x} d x

\frac{d}{d x} (1 - e^{- x} sin (y))

What is the derivative of y=x^{2cos(x)} ?
The derivative of y=x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)
What is the first derivative of y=x^{2cos(x)} ?
The first derivative of y=x^{2cos(x)} is 2x^{2cos(x)}(-sin(x)ln(x)+(cos(x))/x)