What is the solution for xy(dy)/(dx)+4x^2+y^2=0 ?

The solution for xy(dy)/(dx)+4x^2+y^2=0 is y=(sqrt(-2x^4+c_{1)})/x ,y=-(sqrt(-2x^4+c_{1)})/x

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xy(dy)/(dx)+4x^2+y^2=0

x y \frac{d y}{d x} + 4 x^{2} + y^{2} = 0

y = \frac{- 2 x ^{4} + c _{1}}{x}, y = - \frac{- 2 x ^{4} + c _{1}}{x}

Solution steps

x y \frac{d y}{d x} + 4 x^{2} + y^{2} = 0

Solve Bernoulli ODE:

y = \frac{- 2 x ^{4} + c _{1}}{x}, y = - \frac{- 2 x ^{4} + c _{1}}{x}

y = \frac{- 2 x ^{4} + c _{1}}{x}, y = - \frac{- 2 x ^{4} + c _{1}}{x}

\frac{d}{d x} (\frac{5}{2 x ^{2}})

x = y^{2} - 4 y, x = 2 y - y^{2}

\int \frac{1}{t ^{2} 400 - t ^{2}} d t

\frac{d}{d x} (cos (arctan (3 x)))

\int_{0}^{\frac{1}{10}} x ln (10 x) d x

What is the solution for xy(dy)/(dx)+4x^2+y^2=0 ?
The solution for xy(dy)/(dx)+4x^2+y^2=0 is y=(sqrt(-2x^4+c_{1)})/x ,y=-(sqrt(-2x^4+c_{1)})/x