What is the tangent of y=x^2,\at x=-3/4 ?

The tangent of y=x^2,\at x=-3/4 is y=-3/2 x-9/16

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tangent of y=x^2,\at x=-3/4

tangent of

y = x^{2}, at x = - \frac{3}{4}

y = - \frac{3}{2} x - \frac{9}{16}

Solution steps

Find the tangent point:

(- \frac{3}{4}, \frac{9}{16})

Find the slope of

y = x^{2} : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(- \frac{3}{4}, \frac{9}{16}) : y = - \frac{3}{2} x - \frac{9}{16}

y = - \frac{3}{2} x - \frac{9}{16}

What is the tangent of y=x^2,\at x=-3/4 ?
The tangent of y=x^2,\at x=-3/4 is y=-3/2 x-9/16