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Popular Calculus >

area x=y^2,x=y+2

Solution

area

x = y^{2}, x = y + 2

Solution

\frac{9}{2}

+1

Decimal

4.5

Solution steps

Isolate

y

for

x = y^{2} : y = x, y = - x

Isolate

y

for

x = y + 2 : y = x - 2

f_{1} (x) = x

f_{2} (x) = - x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = - x : x = 0

x = x - 2 : x = 4

- x = x - 2 : x = 1

= \int_{0}^{1} ∣ f_{1} (x) - f_{2} (x) ∣ d x + \int_{1}^{4} ∣ f_{1} (x) - f_{3} (x) ∣ d x

= \int_{0}^{1} x - (- x) d x + \int_{1}^{4} x - (x - 2) d x

\int_{0}^{1} x - (- x) d x = \frac{4}{3}

\int_{1}^{4} x - (x - 2) d x = \frac{19}{6}

= \frac{4}{3} + \frac{19}{6}

Simplify

= \frac{9}{2}

Graph

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Frequently Asked Questions (FAQ)

What is area x=y^2,x=y+2 ?
The answer to area x=y^2,x=y+2 is 9/2