What is laplacetransform e^{-2t-5} ?

The answer to laplacetransform e^{-2t-5} is 1/(e^5(s+2))

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laplacetransform e^{-2t-5}

laplace transform

e^{- 2 t - 5}

\frac{1}{e ^{5} ( s + 2 )}

Solution steps

L {e^{- 2 t - 5}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{- 5} L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= e^{- 5} \frac{1}{s + 2}

Refine

e^{- 5} \frac{1}{s + 2} : \frac{1}{e ^{5} ( s + 2 )}

= \frac{1}{e ^{5} ( s + 2 )}

What is laplacetransform e^{-2t-5} ?
The answer to laplacetransform e^{-2t-5} is 1/(e^5(s+2))