What is the tangent of y=2x^2-9x+7 ?

The tangent of y=2x^2-9x+7 is y=(4a_{0}-9)x-2a_{0}^2+7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of y=2x^2-9x+7

tangent of

y = 2 x^{2} - 9 x + 7

y = (4 a_{0} - 9) x - 2 a_{0}^{2} + 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} - 9 a_{0} + 7)

Find the slope of

y = 2 x^{2} - 9 x + 7 : \frac{d y}{d x} = 4 x - 9

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4 a_{0} - 9

Find the line with slope m=

4 a_{0} - 9

and passing through

(a_{0}, 2 a_{0}^{2} - 9 a_{0} + 7) : y = (4 a_{0} - 9) x - 2 a_{0}^{2} + 7

y = (4 a_{0} - 9) x - 2 a_{0}^{2} + 7

What is the tangent of y=2x^2-9x+7 ?
The tangent of y=2x^2-9x+7 is y=(4a_{0}-9)x-2a_{0}^2+7