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Popular Calculus >

integral of cos^4(xsi)n^3x

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Solution

∫cos4(xsi)n3xdx

Solution

128s2i2n3​(24s2i2x2+128sixcos3(six)sin(six)−12sixsin(4six)+32cos4(six)−3cos(4six))+C
Solution steps
∫cos4(xsi)n3xdx
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=n3⋅∫cos4(six)xdx
Apply u-substitution
=n3⋅∫s2i2ucos4(u)​du
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=n3s2i21​⋅∫ucos4(u)du
Apply Integration By Parts
=n3s2i21​(u(cos3(u)sin(u)+83​(u−41​sin(4u)))−∫cos3(u)sin(u)+83​(u−41​sin(4u))du)
∫cos3(u)sin(u)+83​(u−41​sin(4u))du=−4cos4(u)​+83​(2u2​+161​cos(4u))
=n3s2i21​(u(cos3(u)sin(u)+83​(u−41​sin(4u)))−(−4cos4(u)​+83​(2u2​+161​cos(4u))))
Substitute back u=six=n3s2i21​(six(cos3(six)sin(six)+83​(six−41​sin(4six)))−(−4cos4(six)​+83​(2(six)2​+161​cos(4six))))
Simplify n3s2i21​(six(cos3(six)sin(six)+83​(six−41​sin(4six)))−(−4cos4(six)​+83​(2(six)2​+161​cos(4six)))):128s2i2n3​(24s2i2x2+128sixcos3(six)sin(six)−12sixsin(4six)+32cos4(six)−3cos(4six))
=128s2i2n3​(24s2i2x2+128sixcos3(six)sin(six)−12sixsin(4six)+32cos4(six)−3cos(4six))
Add a constant to the solution=128s2i2n3​(24s2i2x2+128sixcos3(six)sin(six)−12sixsin(4six)+32cos4(six)−3cos(4six))+C

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