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Popular Calculus >

d/(dt)(t^2+1)

Solution

\frac{d}{d t} (t^{2} + 1)

Solution

2 t

Solution steps

\frac{d}{d t} (t^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) + \frac{d}{d t} (1)

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (1) = 0

= 2 t + 0

Simplify

= 2 t

Graph

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Frequently Asked Questions (FAQ)

What is the d/(dt)(t^2+1) ?
The d/(dt)(t^2+1) is 2t
What is the first d/(dt)(t^2+1) ?
The first d/(dt)(t^2+1) is 2t