What is the solution for y^'=ytan(t)+sin(t) ?

The solution for y^'=ytan(t)+sin(t) is y=(sin^2(t))/(2cos(t))+(c_{1})/(cos(t))

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y^'=ytan(t)+sin(t)

y^{^{'}} = y tan (t) + sin (t)

y = \frac{sin ^{2} ( t )}{2 cos ( t )} + \frac{c _{1}}{cos ( t )}

Solution steps

y^{'} (t) = y tan (t) + sin (t)

Solve linear ODE:

y = \frac{sin ^{2} ( t )}{2 cos ( t )} + \frac{c _{1}}{cos ( t )}

y = \frac{sin ^{2} ( t )}{2 cos ( t )} + \frac{c _{1}}{cos ( t )}

What is the solution for y^'=ytan(t)+sin(t) ?
The solution for y^'=ytan(t)+sin(t) is y=(sin^2(t))/(2cos(t))+(c_{1})/(cos(t))