What is the integral of 7x^2+5x-5 ?

The integral of 7x^2+5x-5 is (7x^3)/3+(5x^2)/2-5x+C

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integral of 7x^2+5x-5

\int 7 x^{2} + 5 x - 5 d x

\frac{7 x ^{3}}{3} + \frac{5 x ^{2}}{2} - 5 x + C

Solution steps

\int 7 x^{2} + 5 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 x^{2} d x + \int 5 x d x - \int 5 d x

\int 7 x^{2} d x = \frac{7 x ^{3}}{3}

\int 5 x d x = \frac{5 x ^{2}}{2}

\int 5 d x = 5 x

= \frac{7 x ^{3}}{3} + \frac{5 x ^{2}}{2} - 5 x

Add a constant to the solution

= \frac{7 x ^{3}}{3} + \frac{5 x ^{2}}{2} - 5 x + C

\frac{\partial}{\partial x} (x sin^{2} (x))

\int c x^{2} d x

\frac{\partial}{\partial u ( v )} (\frac{e ^{v}}{u ( v ) + v ^{2}})

\int \frac{x ^{2} - 2}{x - 1} d x

\frac{d x}{d t} = k + x r

What is the integral of 7x^2+5x-5 ?
The integral of 7x^2+5x-5 is (7x^3)/3+(5x^2)/2-5x+C