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Popular Calculus >

integral of 8^{2x+6}

Solution

\int 8^{2 x + 6} d x

Solution

32 (2 x + 6) + C

Solution steps

\int 8^{2 x + 6} d x

Apply u-substitution

= \int 32 d u

Integral of a constant:

\int a d x = a x

= 32 u

Substitute back

u = 2 x + 6

= 32 (2 x + 6)

Add a constant to the solution

= 32 (2 x + 6) + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 8^{2x+6} ?
The integral of 8^{2x+6} is 32(2x+6)+C