What is the derivative of 1/(x+2) ?

The derivative of 1/(x+2) is -1/((x+2)^2)

What is the first derivative of 1/(x+2) ?

The first derivative of 1/(x+2) is -1/((x+2)^2)

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derivative of

\frac{1}{x + 2}

- \frac{1}{( x + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x + 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

= - \frac{1}{( x + 2 ) ^{2}} \frac{d}{d x} (x + 2)

\frac{d}{d x} (x + 2) = 1

= - \frac{1}{( x + 2 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 2 ) ^{2}}

\int \frac{7 t ^{3} + t ^{2}}{t} d t

2^{8 - x^{2}}

\int \frac{1}{4 x ^{2} + 2} d x

n = 0 \sum \infty \frac{( n ^{n} )}{n !}

\int \frac{1}{z} d z

What is the derivative of 1/(x+2) ?
The derivative of 1/(x+2) is -1/((x+2)^2)
What is the first derivative of 1/(x+2) ?
The first derivative of 1/(x+2) is -1/((x+2)^2)