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Popular >

tangent of y=(5x)/(1+x^2),(4, 20/17)

Solution

tangent of

y = \frac{5 x}{1 + x ^{2}}, (4, \frac{20}{17})

Solution

y = - \frac{75}{289} x + \frac{640}{289}

Solution steps

Find the slope of

y = \frac{5 x}{1 + x ^{2}} : \frac{d y}{d x} = \frac{5 ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

Compute the slope of

y = \frac{5 x}{1 + x ^{2}}

at

(4, \frac{20}{17}) : m = - \frac{75}{289}

Find the line with slope m=

- \frac{75}{289}

and passing through

(4, \frac{20}{17}) : y = - \frac{75}{289} x + \frac{640}{289}

y = - \frac{75}{289} x + \frac{640}{289}

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\int \frac{7 - 98 x}{81 - 49 x ^{2}} d x

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y = x^{0.4}

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\frac{d}{d x} ((x + 1)^{3} (x - 2))

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\frac{d}{d x} (9 x + 5)

integral of sec(32x)tan(32x)

\int sec (32 x) tan (32 x) d x

Frequently Asked Questions (FAQ)

What is the tangent of y=(5x)/(1+x^2),(4, 20/17) ?
The tangent of y=(5x)/(1+x^2),(4, 20/17) is y=-75/289 x+640/289