What is the integral of (sqrt(2y)) ?

The integral of (sqrt(2y)) is sqrt(2)ysqrt(y)-(sqrt(2))/3 y^{3/2}+C

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integral of (sqrt(2y))

\int (2 y) d y

2 y y - \frac{2}{3} y^{\frac{3}{2}} + C

Solution steps

\int 2 y d y

Apply Integration By Parts

: 2 y y - \int \frac{y}{2} d y

= 2 y y - \int \frac{y}{2} d y

\int \frac{y}{2} d y = \frac{2}{3} y^{\frac{3}{2}}

= 2 y y - \frac{2}{3} y^{\frac{3}{2}}

Add a constant to the solution

= 2 y y - \frac{2}{3} y^{\frac{3}{2}} + C

y = (\frac{1}{3})^{x}

\int - 4 ln (x^{2} - 1) d x

n = 1 \sum \infty n (1)^{n}

7 x^{2} + 8 x

\int \frac{x ^{2}}{x ^{2} + 4 x - 12} d x

What is the integral of (sqrt(2y)) ?
The integral of (sqrt(2y)) is sqrt(2)ysqrt(y)-(sqrt(2))/3 y^{3/2}+C