What is (\partial)/(\partial x)(2cos(x)) ?

The answer to (\partial)/(\partial x)(2cos(x)) is -2sin(x)

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(\partial)/(\partial x)(2cos(x))

\frac{\partial}{\partial x} (2 cos (x))

- 2 sin (x)

Solution steps

\frac{\partial}{\partial x} (2 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 2 (- sin (x))

Simplify

= - 2 sin (x)

\int 3 y e^{y^{3}} d y

f (x) = ln (x - 4)

\int - cos^{2} (t) d t

\frac{\partial}{\partial x} (2^{x^{2} - y^{5}})

x^{3} - 8 x^{2} + 5 x - 2

What is (\partial)/(\partial x)(2cos(x)) ?
The answer to (\partial)/(\partial x)(2cos(x)) is -2sin(x)