What is the solution for derivative of f(x)=8^{(x^2+4x)} ?

The solution for derivative of f(x)=8^{(x^2+4x)} is f(x)=integral of 8^{x^2+4x}

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derivative of f(x)=8^{(x^2+4x)}

\frac{d}{d x} f (x) = 8^{(x^{2} + 4 x)}

f (x) = \int 8^{x^{2} + 4 x} d x

Solution steps

\frac{df}{d x} = 8^{(x^{2} + 4 x)}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int 8^{x^{2} + 4 x} d x

f (x) = \int 8^{x^{2} + 4 x} d x

What is the solution for derivative of f(x)=8^{(x^2+4x)} ?
The solution for derivative of f(x)=8^{(x^2+4x)} is f(x)=integral of 8^{x^2+4x}