What is the tangent of f(x)= 5/x ,(3, 5/3) ?

The tangent of f(x)= 5/x ,(3, 5/3) is y=-5/9 x+10/3

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tangent of f(x)= 5/x ,(3, 5/3)

tangent of

f (x) = \frac{5}{x}, (3, \frac{5}{3})

y = - \frac{5}{9} x + \frac{10}{3}

Solution steps

Find the slope of

f (x) = \frac{5}{x} : \frac{df ( x )}{d x} = - \frac{5}{x ^{2}}

Compute the slope of

f (x) = \frac{5}{x}

(3, \frac{5}{3}) : m = - \frac{5}{9}

Find the line with slope m=

- \frac{5}{9}

and passing through

(3, \frac{5}{3}) : y = - \frac{5}{9} x + \frac{10}{3}

y = - \frac{5}{9} x + \frac{10}{3}

\frac{\partial}{\partial t} (e^{- 2 x} cos (9 π t))

\frac{1}{2} arctan (2 x)

n = 1 \sum \infty 3 e^{- 4 n}

f (x) = \frac{1}{x ^{2} + 4}, (1, \frac{1}{5})

\int 3 e^{x} - 3 x e^{x^{2}} d x

What is the tangent of f(x)= 5/x ,(3, 5/3) ?
The tangent of f(x)= 5/x ,(3, 5/3) is y=-5/9 x+10/3