What is the sum from n=0 to infinity of (2n)/(n+3) ?

The sum from n=0 to infinity of (2n)/(n+3) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (2n)/(n+3)

n = 0 \sum \infty \frac{2 n}{n + 3}

diverges

Solution steps

n = 0 \sum \infty \frac{2 n}{n + 3}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 0 \sum \infty \frac{n}{n + 3}

Apply Series Divergence Test:

diverges

= 2 diverges

= diverges

x \frac{d y}{d x} + y = - 5 x y^{2}

\int x^{4} - \frac{2}{x} d x

\frac{\partial}{\partial x} ((x + y) ln (x y))

x \to 0 lim (\frac{4}{x ^{5}})

\frac{d}{d x} (x^{2} sin (x))

What is the sum from n=0 to infinity of (2n)/(n+3) ?
The sum from n=0 to infinity of (2n)/(n+3) is diverges