What is the derivative of Axe^x ?

The derivative of Axe^x is A(e^x+e^xx)

What is the first derivative of Axe^x ?

The first derivative of Axe^x is A(e^x+e^xx)

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\frac{d}{d x} (A x e^{x})

A (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (A x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= A \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= A (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= A (1 \cdot e^{x} + e^{x} x)

Simplify

= A (e^{x} + e^{x} x)

(- 1, 2), (3, - 3)

\frac{d}{d x} (2 \cdot ln (x))

sin^{3} (x)

x \to 0 lim (x + 1 - 1)

\int \frac{4 x ^{2} + 4}{( x ^{2} - 2 x + 2 ) ^{2}} d x

What is the derivative of Axe^x ?
The derivative of Axe^x is A(e^x+e^xx)
What is the first derivative of Axe^x ?
The first derivative of Axe^x is A(e^x+e^xx)