What is the solution for y^3dx-x^3dy=0 ?

The solution for y^3dx-x^3dy=0 is y=sqrt(-(x^2)/(-1+2c_{1)x^2)},y=-sqrt(-(x^2)/(-1+2c_{1)x^2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^3dx-x^3dy=0

y^{3} d x - x^{3} d y = 0

y = - \frac{x ^{2}}{- 1 + 2 c _{1} x ^{2}}, y = - - \frac{x ^{2}}{- 1 + 2 c _{1} x ^{2}}

Solution steps

y^{3} d x - x^{3} d y = 0

Solve separable ODE:

y = - \frac{x ^{2}}{- 1 + 2 c _{1} x ^{2}}, y = - - \frac{x ^{2}}{- 1 + 2 c _{1} x ^{2}}

y = - \frac{x ^{2}}{- 1 + 2 c _{1} x ^{2}}, y = - - \frac{x ^{2}}{- 1 + 2 c _{1} x ^{2}}

\int 25 x e^{5 x} d x

\int \frac{4 x}{e ^{3 x}} d x

(0.3) (4)

\frac{d}{d x} (\frac{x ^{2} + x + 1}{x ^{\frac{3}{2}}})

(- 4, - 3), (3, - 3)

What is the solution for y^3dx-x^3dy=0 ?
The solution for y^3dx-x^3dy=0 is y=sqrt(-(x^2)/(-1+2c_{1)x^2)},y=-sqrt(-(x^2)/(-1+2c_{1)x^2)}