What is area e^{8x}-e^{2x},x=1 ?

The answer to area e^{8x}-e^{2x},x=1 is (e^8-4e^2+3)/8

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area e^{8x}-e^{2x},x=1

area

e^{8 x} - e^{2 x}, x = 1

\frac{e ^{8} - 4 e ^{2} + 3}{8}

Solution steps

Apply the area formula:

\int_{0}^{1} e^{8 x} - e^{2 x} d x

Solve

\int_{0}^{1} e^{8 x} - e^{2 x} d x : \frac{e ^{8} - 4 e ^{2} + 3}{8}

The area is:

= \frac{e ^{8} - 4 e ^{2} + 3}{8}

y = x - 6, y^{2} = 2 x + 108

x \to 3 lim (\frac{13 sin ( 6 x )}{x})

\frac{d}{d x} (2 x - 15)

f (x) = ln (c^{3} - 1)

What is area e^{8x}-e^{2x},x=1 ?
The answer to area e^{8x}-e^{2x},x=1 is (e^8-4e^2+3)/8