What is the d/(dt)(-2asin(2t)+bcos(2t)*2) ?

The d/(dt)(-2asin(2t)+bcos(2t)*2) is -4acos(2t)-4bsin(2t)

What is the first d/(dt)(-2asin(2t)+bcos(2t)*2) ?

The first d/(dt)(-2asin(2t)+bcos(2t)*2) is -4acos(2t)-4bsin(2t)

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\frac{d}{d t} (- 2 a sin (2 t) + b cos (2 t) \cdot 2)

- 4 a cos (2 t) - 4 b sin (2 t)

Solution steps

\frac{d}{d t} (- 2 a sin (2 t) + b cos (2 t) \cdot 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (2 a sin (2 t)) + \frac{d}{d t} (b cos (2 t) \cdot 2)

\frac{d}{d t} (2 a sin (2 t)) = 4 a cos (2 t)

\frac{d}{d t} (b cos (2 t) \cdot 2) = - 4 b sin (2 t)

= - 4 a cos (2 t) - 4 b sin (2 t)

What is the d/(dt)(-2asin(2t)+bcos(2t)*2) ?
The d/(dt)(-2asin(2t)+bcos(2t)*2) is -4acos(2t)-4bsin(2t)
What is the first d/(dt)(-2asin(2t)+bcos(2t)*2) ?
The first d/(dt)(-2asin(2t)+bcos(2t)*2) is -4acos(2t)-4bsin(2t)