What is (\partial)/(\partial x)(e^{-y}cos(x)) ?

The answer to (\partial)/(\partial x)(e^{-y}cos(x)) is -e^{-y}sin(x)

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(\partial)/(\partial x)(e^{-y}cos(x))

\frac{\partial}{\partial x} (e^{- y} cos (x))

- e^{- y} sin (x)

Solution steps

\frac{\partial}{\partial x} (e^{- y} cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- y} \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= e^{- y} (- sin (x))

Simplify

= - e^{- y} sin (x)

\int \frac{1}{x + x + 1} d x

\frac{d y}{d t} = e^{- 3 t}

cos^{x} (x)

\frac{d ^{2}}{d x ^{2}} (\frac{2 x}{x ^{2} + 1})

\frac{d}{d x} (\frac{1}{2 x ^{2} - 3 x + 1})

What is (\partial)/(\partial x)(e^{-y}cos(x)) ?
The answer to (\partial)/(\partial x)(e^{-y}cos(x)) is -e^{-y}sin(x)