What is the first derivative of 2x-3 ?

The first derivative of 2x-3 is 2

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derivative of 2x-3

derivative of

2 x - 3

2

Solution steps

\frac{d}{d x} (2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 2 - 0

Simplify

= 2

x \to - 1 - lim (\frac{1}{x + 1})

\frac{d y}{d x} + y = x y^{8}

f (x) = 5 x + 2

2 (x^{2} + y^{2}) d x + 7 x y d y = 0

f (x) = x^{2} cos (x)