What is the derivative of sqrt(2+cos(2x)) ?

The derivative of sqrt(2+cos(2x)) is -(sin(2x))/(sqrt(2+cos(2x)))

What is the first derivative of sqrt(2+cos(2x)) ?

The first derivative of sqrt(2+cos(2x)) is -(sin(2x))/(sqrt(2+cos(2x)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (2 + cos (2 x))

- \frac{sin ( 2 x )}{2 + cos ( 2 x )}

Solution steps

\frac{d}{d x} (2 + cos (2 x))

Apply the chain rule:

\frac{1}{2 2 + cos ( 2 x )} \frac{d}{d x} (2 + cos (2 x))

= \frac{1}{2 2 + cos ( 2 x )} \frac{d}{d x} (2 + cos (2 x))

\frac{d}{d x} (2 + cos (2 x)) = - 2 sin (2 x)

= \frac{1}{2 2 + cos ( 2 x )} (- 2 sin (2 x))

Simplify

\frac{1}{2 2 + cos ( 2 x )} (- 2 sin (2 x)) : - \frac{sin ( 2 x )}{2 + cos ( 2 x )}

= - \frac{sin ( 2 x )}{2 + cos ( 2 x )}

What is the derivative of sqrt(2+cos(2x)) ?
The derivative of sqrt(2+cos(2x)) is -(sin(2x))/(sqrt(2+cos(2x)))
What is the first derivative of sqrt(2+cos(2x)) ?
The first derivative of sqrt(2+cos(2x)) is -(sin(2x))/(sqrt(2+cos(2x)))