What is the derivative of (3x^2/2-7/(5x^2)) ?

The derivative of (3x^2/2-7/(5x^2)) is 3x+(14)/(5x^3)

What is the first derivative of (3x^2/2-7/(5x^2)) ?

The first derivative of (3x^2/2-7/(5x^2)) is 3x+(14)/(5x^3)

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\frac{d}{d x} (\frac{3 x ^{2}}{2} - \frac{7}{5 x ^{2}})

3 x + \frac{14}{5 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{3 x ^{2}}{2} - \frac{7}{5 x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3 x ^{2}}{2}) - \frac{d}{d x} (\frac{7}{5 x ^{2}})

\frac{d}{d x} (\frac{3 x ^{2}}{2}) = 3 x

\frac{d}{d x} (\frac{7}{5 x ^{2}}) = - \frac{14}{5 x ^{3}}

= 3 x - (- \frac{14}{5 x ^{3}})

Simplify

= 3 x + \frac{14}{5 x ^{3}}

What is the derivative of (3x^2/2-7/(5x^2)) ?
The derivative of (3x^2/2-7/(5x^2)) is 3x+(14)/(5x^3)
What is the first derivative of (3x^2/2-7/(5x^2)) ?
The first derivative of (3x^2/2-7/(5x^2)) is 3x+(14)/(5x^3)