What is the solution for y^'=8y^2cos(t)+7y^2sin(4t) ?

The solution for y^'=8y^2cos(t)+7y^2sin(4t) is y=-4/(32sin(t)-7cos(4t)+c_{1)}

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y^'=8y^2cos(t)+7y^2sin(4t)

y^{^{'}} = 8 y^{2} cos (t) + 7 y^{2} sin (4 t)

y = - \frac{4}{32 sin ( t ) - 7 cos ( 4 t ) + c _{1}}

Solution steps

y^{'} (t) = 8 y^{2} cos (t) + 7 y^{2} sin (4 t)

Solve separable ODE:

y = - \frac{4}{32 sin ( t ) - 7 cos ( 4 t ) + c _{1}}

y = - \frac{4}{32 sin ( t ) - 7 cos ( 4 t ) + c _{1}}

t an g e n t x^{3} - 2 x + 2

t an g e n t - 6 x^{2} + 5 x

d er i v a t i v e y = (ln (x))^{3}

d er i v a t i v e f (x) = e^{2 - x}

t an g e n t x^{2} + 3, at (x = 1)

What is the solution for y^'=8y^2cos(t)+7y^2sin(4t) ?
The solution for y^'=8y^2cos(t)+7y^2sin(4t) is y=-4/(32sin(t)-7cos(4t)+c_{1)}