What is the derivative of (-1^nx^n) ?

The derivative of (-1^nx^n) is (-1)^nnx^{n-1}

What is the first derivative of (-1^nx^n) ?

The first derivative of (-1^nx^n) is (-1)^nnx^{n-1}

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\frac{d}{d x} ((- 1)^{n} x^{n})

(- 1)^{n} n x^{n - 1}

Solution steps

\frac{d}{d x} ((- 1)^{n} x^{n})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (- 1)^{n} \frac{d}{d x} (x^{n})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (- 1)^{n} n x^{n - 1}

\frac{d}{d x} (\frac{1 + x}{x})

y^{^{''}} + 2 y^{^{'}} - 3 y = 0, y (0) = 4, y^{^{'}} (0) = 1

f (x) = \frac{9}{x - 6}

x \to 0 lim (\frac{x}{sin ( 6 x )})

What is the derivative of (-1^nx^n) ?
The derivative of (-1^nx^n) is (-1)^nnx^{n-1}
What is the first derivative of (-1^nx^n) ?
The first derivative of (-1^nx^n) is (-1)^nnx^{n-1}