What is the tangent of y=10-3x-x^2 ?

The tangent of y=10-3x-x^2 is y=(-2a_{0}-3)x+a_{0}^2+10

Popular >

tangent of y=10-3x-x^2

tangent of

y = 10 - 3 x - x^{2}

y = (- 2 a_{0} - 3) x + a_{0}^{2} + 10

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 10 - 3 a_{0} - a_{0}^{2})

Find the slope of

y = 10 - 3 x - x^{2} : \frac{d y}{d x} = - 2 x - 3

Compute the slope of

y = 10 - 3 x - x^{2}

x = a_{0} : m = - 2 a_{0} - 3

Find the line with slope m=

- 2 a_{0} - 3

and passing through

(a_{0}, 10 - 3 a_{0} - a_{0}^{2}) : y = (- 2 a_{0} - 3) x + a_{0}^{2} + 10

y = (- 2 a_{0} - 3) x + a_{0}^{2} + 10

\frac{d y}{d x} + y cos (x) = 4 cos (x), y (0) = 6

\int 3 x 4 - x^{2} d x

\int sin (3) (θ) cos (6) (θ) d θ

\int_{0}^{1} x e^{- 5 x^{2}} d x

\int_{0}^{1} \frac{5 y}{e ^{2 y}} d y

What is the tangent of y=10-3x-x^2 ?
The tangent of y=10-3x-x^2 is y=(-2a_{0}-3)x+a_{0}^2+10