What is the tangent of y^3=126-x^3,\at x=5 ?

The tangent of y^3=126-x^3,\at x=5 is y=-25x+126

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tangent of y^3=126-x^3,\at x=5

tangent of

y^{3} = 126 - x^{3}, at x = 5

y = - 25 x + 126

Solution steps

Find the tangent point:

(5, 1)

Find the slope of

y^{3} = 126 - x^{3} : \frac{d y}{d x} = - \frac{x ^{2}}{( 126 - x ^{3} ) ^{\frac{2}{3}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 25

Find the line with slope m=

- 25

and passing through

(5, 1) : y = - 25 x + 126

y = - 25 x + 126

What is the tangent of y^3=126-x^3,\at x=5 ?
The tangent of y^3=126-x^3,\at x=5 is y=-25x+126