en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

integral from 0 to 1 of y-y^2

Solution

\int_{0}^{1} y - y^{2} d y

Solution

\frac{1}{6}

+1

Decimal

0.16666 \dots

Solution steps

\int_{0}^{1} y - y^{2} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} y d y - \int_{0}^{1} y^{2} d y

\int_{0}^{1} y d y = \frac{1}{2}

\int_{0}^{1} y^{2} d y = \frac{1}{3}

= \frac{1}{2} - \frac{1}{3}

Simplify

\frac{1}{2} - \frac{1}{3} : \frac{1}{6}

= \frac{1}{6}

Graph

Popular Examples

(\partial)/(\partial x)(y+sin(x))

derivative of 8e^{3x}

integral of+(2x+1)/((x+5)^3)

derivative of 1/(\sqrt[3]{x^2+x+3})

d/(dy)(x-y^3+y^2sin(x))

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of y-y^2 ?
The integral from 0 to 1 of y-y^2 is 1/6