What is the tangent of y=sqrt(x),(16,4) ?

The tangent of y=sqrt(x),(16,4) is y= 1/8 x+2

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tangent of y=sqrt(x),(16,4)

tangent of

y = x, (16, 4)

y = \frac{1}{8} x + 2

Solution steps

Find the slope of

y = x : \frac{d y}{d x} = \frac{1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{8}

Find the line with slope m=

\frac{1}{8}

and passing through

(16, 4) : y = \frac{1}{8} x + 2

y = \frac{1}{8} x + 2

What is the tangent of y=sqrt(x),(16,4) ?
The tangent of y=sqrt(x),(16,4) is y= 1/8 x+2