What is the tangent of y=sqrt(3x+4),(7,5) ?

The tangent of y=sqrt(3x+4),(7,5) is y= 3/10 x+29/10

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tangent of y=sqrt(3x+4),(7,5)

tangent of

y = 3 x + 4, (7, 5)

y = \frac{3}{10} x + \frac{29}{10}

Solution steps

Find the slope of

y = 3 x + 4 : \frac{d y}{d x} = \frac{3}{2 3 x + 4}

Compute the slope of

y = 3 x + 4

(7, 5) : m = \frac{3}{10}

Find the line with slope m=

\frac{3}{10}

and passing through

(7, 5) : y = \frac{3}{10} x + \frac{29}{10}

y = \frac{3}{10} x + \frac{29}{10}

y y^{^{'}} = - x

x \to 1 lim (e^{x - 1} - 1)

f (x) = \frac{x ^{2}}{( 4 + x )}

f (x) = - cot (x) csc (x)

What is the tangent of y=sqrt(3x+4),(7,5) ?
The tangent of y=sqrt(3x+4),(7,5) is y= 3/10 x+29/10