What is the integral of cot(40x) ?

The integral of cot(40x) is 1/40 ln|sin(40x)|+C

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integral of cot(40x)

\int cot (40 x) d x

\frac{1}{40} ln ∣ sin (40 x) ∣ + C

Solution steps

\int cot (40 x) d x

Rewrite using trig identities

= \int \frac{cos ( 40 x )}{sin ( 40 x )} d x

Apply u-substitution

= \int \frac{1}{40 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{40} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{40} ln ∣ u ∣

Substitute back

u = sin (40 x)

= \frac{1}{40} ln ∣ sin (40 x) ∣

Add a constant to the solution

= \frac{1}{40} ln ∣ sin (40 x) ∣ + C

What is the integral of cot(40x) ?
The integral of cot(40x) is 1/40 ln|sin(40x)|+C