(dy)/(dt)=((4y^2-t^2))/(2ty)

解答

\frac{d y}{d t} = \frac{( 4 y ^{2} - t ^{2} )}{2 t y}

y = \frac{t 2 c _{1} t ^{2} + 1}{2}, y = - \frac{t 2 c _{1} t ^{2} + 1}{2}

求解步骤

\frac{d y}{d t} = \frac{( 4 y ^{2} - t ^{2} )}{2 t y}

求解贝努力方程:

y = \frac{t 2 c _{1} t ^{2} + 1}{2}, y = - \frac{t 2 c _{1} t ^{2} + 1}{2}

y = \frac{t 2 c _{1} t ^{2} + 1}{2}, y = - \frac{t 2 c _{1} t ^{2} + 1}{2}