What is the solution for y^'+2xy=1 ?

The solution for y^'+2xy=1 is y=(sqrt(pi)\erfi(x))/(2e^{x^2)}+(c_{1})/(e^{x^2)}

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y^'+2xy=1

y^{^{'}} + 2 x y = 1

y = \frac{π erfi ( x )}{2 e ^{x^{2}}} + \frac{c _{1}}{e ^{x^{2}}}

Solution steps

y^{'} (x) + 2 x y = 1

Solve linear ODE:

y = \frac{π erfi ( x )}{2 e ^{x^{2}}} + \frac{c _{1}}{e ^{x^{2}}}

y = \frac{π erfi ( x )}{2 e ^{x^{2}}} + \frac{c _{1}}{e ^{x^{2}}}

What is the solution for y^'+2xy=1 ?
The solution for y^'+2xy=1 is y=(sqrt(pi)\erfi(x))/(2e^{x^2)}+(c_{1})/(e^{x^2)}