What is the derivative of e^{x^4}+7x ?

The derivative of e^{x^4}+7x is e^{x^4}*4x^3+7

What is the first derivative of e^{x^4}+7x ?

The first derivative of e^{x^4}+7x is e^{x^4}*4x^3+7

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\frac{d}{d x} (e^{x^{4}} + 7 x)

e^{x^{4}} \cdot 4 x^{3} + 7

Solution steps

\frac{d}{d x} (e^{x^{4}} + 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x^{4}}) + \frac{d}{d x} (7 x)

\frac{d}{d x} (e^{x^{4}}) = e^{x^{4}} \cdot 4 x^{3}

\frac{d}{d x} (7 x) = 7

= e^{x^{4}} \cdot 4 x^{3} + 7

What is the derivative of e^{x^4}+7x ?
The derivative of e^{x^4}+7x is e^{x^4}*4x^3+7
What is the first derivative of e^{x^4}+7x ?
The first derivative of e^{x^4}+7x is e^{x^4}*4x^3+7