What is the tangent of y^2+xy+x^2=1,(0,1) ?

The tangent of y^2+xy+x^2=1,(0,1) is y=-1/2 x+1

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tangent of y^2+xy+x^2=1,(0,1)

tangent of

y^{2} + x y + x^{2} = 1, (0, 1)

y = - \frac{1}{2} x + 1

Solution steps

Find the slope of

y^{2} + x y + x^{2} = 1 : \frac{d y}{d x} = \frac{- y - 2 x}{2 y + x}

Compute the slope of

y^{2} + x y + x^{2} = 1

(0, 1) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(0, 1) : y = - \frac{1}{2} x + 1

y = - \frac{1}{2} x + 1

x \frac{d y}{d x} = x^{- 3} - 2 y

\int_{1}^{4} \frac{3}{x} d x

\frac{3}{2 s ^{2} + 3 s + 1}

\frac{d y}{d x} = 2 y e^{x + 7}

x \to 1 - lim (3)

What is the tangent of y^2+xy+x^2=1,(0,1) ?
The tangent of y^2+xy+x^2=1,(0,1) is y=-1/2 x+1